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Time Limit: 2.0 s

Memory Limit: 128.0 MB

Background

Special for beginners, ^_^

Description

Given two integers x and y, print the sum.

Format

Input

Two integers x and y, satisfying 0 <= x, y <= 32767.

Output

One integer, the sum of x and y.

Sample

18820 26832

45652

1123 5687

6810

Hint

C Code

#include <stdio.h>
int main(void)
{
    int a, b;
    scanf("%d%d", &a, &b);
    printf("%d\n", a + b);
    return 0;
}

C++ Code

#include <iostream>
using namespace std;
int main()
{
    int a, b;
    cin >> a >> b;
    cout << a + b << endl;
    return 0;
}

C# Code

using System;
using System.Linq;

class Program {
    public static void Main(string[] args) {
        Console.WriteLine(Console.ReadLine().Split().Select(int.Parse).Sum());
    }
}

Python Code

a, b = list(map(int, input().split()))
print(a + b)

Java Code

import java.io.*;
import java.util.Scanner;

public class Main {

    /**
     * @param args
     * @throws IOException 
     */
    public static void main(String[] args) throws IOException {
        Scanner sc = new Scanner(System.in);
        int a = sc.nextInt();
        int b = sc.nextInt();
        System.out.println(a + b);
    }
}

Ruby Code

a, b = gets.split.map(&:to_i)
puts(a + b)

Kotlin

fun main() {
    val inp = readln().split(" ")
    val a = inp[0].toInt()
    val b = inp[1].toInt()
    val sum = a + b 
    println(sum)
}