Wrong Answer
Code
def xor(n):
if n % 4 == 0:
return n
elif n % 4 == 1:
return 1
elif n % 4 == 2:
return n + 1
else:
return 0
t = int(input())
if 1 <= t <= 10 ** 5:
for i in range(t):
n = int(input())
xor(n)
Information
- Submit By
- Type
- Submission
- Problem
- P1009 XOR Love
- Language
- Python 3 (Python 3.12.3)
- Submit At
- 2023-12-31 12:55:20
- Judged At
- 2024-11-11 03:46:48
- Judged By
- Score
- 0
- Total Time
- 36ms
- Peak Memory
- 3.133 MiB