Accepted
Code
#include <stdio.h>
// Function to count the number of odd numbers from 1 to N
int countOddNumbers(int N) {
// Since every alternate number is odd, we can simply divide N by 2 to get the count of odd numbers
// For example, if N = 5, there are (5+1)/2 = 3 odd numbers (1, 3, 5)
return (N + 1) / 2;
}
int main() {
int T;
scanf("%d", &T);
while (T--) {
int N;
scanf("%d", &N);
printf("%d\n", countOddNumbers(N));
}
return 0;
}
Information
- Submit By
- Type
- Submission
- Problem
- P1041 Odd number
- Contest
- TLE_Headquarters - round #1
- Language
- C99 (GCC 13.2.0)
- Submit At
- 2024-03-27 16:10:48
- Judged At
- 2024-11-11 03:39:31
- Judged By
- Score
- 100
- Total Time
- 1ms
- Peak Memory
- 388.0 KiB