/ SeriousOJ /

Record Detail

Accepted


  
# Status Time Cost Memory Cost
#1 Accepted 4ms 3.453 MiB
#2 Accepted 5ms 3.469 MiB
#3 Accepted 5ms 3.457 MiB
#4 Accepted 5ms 3.461 MiB
#5 Accepted 66ms 3.68 MiB
#6 Accepted 63ms 11.066 MiB
#7 Accepted 63ms 11.062 MiB
#8 Accepted 64ms 11.105 MiB
#9 Accepted 59ms 11.062 MiB
#10 Accepted 61ms 11.008 MiB
#11 Accepted 54ms 11.25 MiB
#12 Accepted 61ms 11.102 MiB
#13 Accepted 57ms 11.109 MiB
#14 Accepted 58ms 11.246 MiB
#15 Accepted 57ms 11.246 MiB
#16 Accepted 59ms 11.242 MiB

Code

#include <bits/stdc++.h>
#define endl '\n'
using namespace std;
#define ll long long
#define mod 1000000007
// #define int long long
#define all(x)      x.begin(),x.end()
#define allr(x)     x.rbegin(),x.rend()
#define CheckBit(x,k)   (x & (1LL << k))
#define SetBit(x,k)     (x |= (1LL << k))
#define ClearBit(x,k)   (x &= ~(1LL << k))
#define LSB(mask)       __builtin_ctzll(mask)
#define MSB(mask)       63-__builtin_clzll(mask) 
#define print(x)    cout << #x << " : " << x << endl
#define error1(x)   cerr << #x << " = " << (x) <<endl
#define coutall(v)  for(auto &it: v) cout<<it<<' '; cout<<endl
#define Abid_52     ios::sync_with_stdio(false);cin.tie(0),cin.tie(0)
#define error2(a,b) cerr<<"( "<<#a<<" , "<<#b<<" ) = ( "<<(a)<<" , "<<(b)<<" )\n"
#define UNIQUE(x)   sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()
template <typename T, typename U> T ceil(T x, U y) {return (x > 0 ? (x + y - 1) / y : x / y);}
template <typename T, typename U> T floor(T x, U y) {return (x > 0 ? x / y : (x - y + 1) / y);}
const int N = 1e5 + 10;
int n;
vector<int> a(N), b(N), c(N);
int dp[N][5];
int rec(int i, int prev)
{
    if (i >= n)
    {
        return 0;
    }
    if (dp[i][prev] != -1)
    {
        return dp[i][prev];
    }
    int ans = -1000000000;
    if (prev == 0)
    {
        ans = a[i] + rec(i + 1, 1);
        ans = max(ans, b[i] + rec(i + 1, 2));
        ans = max(ans, c[i] + rec(i + 1, 3));
    }
    else
    {
        if (prev == 1)
        {
            ans = max(ans, b[i] + rec(i + 1, 2));
            ans = max(ans, c[i] + rec(i + 1, 3));
        }
        else if (prev == 2)
        {
            ans = max(ans, a[i] + rec(i + 1, 1));
            ans = max(ans, c[i] + rec(i + 1, 3));
        }
        else
        {
            ans = max(ans, a[i] + rec(i + 1, 1));
            ans = max(ans, b[i] + rec(i + 1, 2));
        }
    }
    return dp[i][prev] = ans;
}
void solve()
{
    for (int i = 0; i < N; i++)
    {
        for (int j = 0; j < 5; j++)
        {
            dp[i][j] = -1;
        }
    }
    cin >> n;
    for (int i = 0; i < n; i++)
    {
        cin >> a[i];
    }
    for (int i = 0; i < n; i++)
    {
        cin >> b[i];
    }
    for (int i = 0; i < n; i++)
    {
        cin >> c[i];
    }
    cout << rec(0, 0) << endl;
}
int32_t main()
{
    Abid_52;
    int t = 1;
    cin >> t;
    for (int tc = 1; tc <= t; ++tc)
    {
        // cout << "Case " << tc << ": ";
        solve();
    }
}

Information

Submit By
Type
Submission
Problem
P1046 Maximum sum in 3-array
Language
C++20 (G++ 13.2.0)
Submit At
2024-03-28 10:47:27
Judged At
2024-11-11 03:36:34
Judged By
Score
100
Total Time
66ms
Peak Memory
11.25 MiB