/ SeriousOJ /

Record Detail

Time Exceeded


  
# Status Time Cost Memory Cost
#1 Accepted 2ms 544.0 KiB
#2 Accepted 29ms 1.547 MiB
#3 Accepted 274ms 1.699 MiB
#4 Accepted 274ms 1.695 MiB
#5 Time Exceeded ≥1076ms ≥2.09 MiB
#6 Time Exceeded ≥1070ms ≥2.09 MiB

Code

/* 
 *   @author:- MAHMUDUL HASAN SAKIB
 *   DATE & TIME :-2024-08-16 21:13:27
 *   BANGLADESH , SYLHET.
 */ 

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <deque>
#include <forward_list>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <numeric>
#include <optional>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <type_traits>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
#define fi first
#define se second
#define endl '\n'
#define ll long long
#define ld long double
#define pb push_back
#define mp make_pair
#define vi vector<ll>
#define maxn 500005
#define mod 1000000007
#define inf 1000000007
#define pii pair<ll,ll>
#define vii vector<pii>
#define sz(x) (int)x.size()
#define all(x) x.begin(), x.end()
#define lcm(a,b) ((a*b)/__gcd(a,b));
#define srt(v) sort(v.begin(),v.end())
#define rsrt(v) sort(v.rbegin(),v.rend())
#define rep(i, a, b) for(int i = (a); i < (b); i++)
#define per(i, a, b) for(int i = (a); i > (b); i--)
#define rev_str(str) reverse(str.begin(),str.end());
#define print(v) for(auto e:v) cout<<e<<" "; cout<<endl;
#define printp(v) for(auto e:v) cout<<e.first<<" "<<e.second<<endl;
#define fast ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
//ll q[200005];
void solve(){
    ll n;cin>>n;
    vi p(n);
    vii s;
    rep(i,0,n){
        cin>>p[i];
        //s.emplace_back(p[i],i+1);
    }
    //srt(s);
    //for (const auto& i : s) {
      //  cout << "First: " << i.first << ", Second: " << i.second << endl;
    //}

    ll q;cin>>q;
    vi r(q);
    rep(i,0,q){
        cin>>r[i];
        //cout<<s[0].second<<endl;
        //srt(s);
        int x = min_element(p.begin(), p.end()) - p.begin();
        cout << x+1 << endl;
        p[x] = r[i];
    }
}

int main() {
    fast
    ll t=1;//cin>>t;
    while (t--) {
        solve();
    }
    return 0;
}

Information

Submit By
Type
Submission
Problem
P1086 KuZ the Position
Contest
Bangladesh 2.0
Language
C++20 (G++ 13.2.0)
Submit At
2024-08-16 16:13:40
Judged At
2024-10-03 13:28:07
Judged By
Score
60
Total Time
≥1076ms
Peak Memory
≥2.09 MiB