#include <bits/stdc++.h>
#define endl '\n'
#define F first
#define S second
using namespace std;
#define ll long long
#define pb push_back
#define mod 1000000007
// #define int long long
#define all(x) x.begin(),x.end()
#define allr(x) x.rbegin(),x.rend()
#define CheckBit(x,k) (x & (1LL << k))
#define SetBit(x,k) (x |= (1LL << k))
#define ClearBit(x,k) (x &= ~(1LL << k))
#define LSB(mask) __builtin_ctzll(mask)
#define MSB(mask) 63-__builtin_clzll(mask)
#define print(x) cout << #x << " : " << x << endl
#define error1(x) cerr << #x << " = " << (x) <<endl
#define coutall(v) for(auto &it: v) cout<<it<<' '; cout<<endl
#define Abid_52 ios::sync_with_stdio(false);cin.tie(0),cin.tie(0)
#define error2(a,b) cerr<<"( "<<#a<<" , "<<#b<<" ) = ( "<<(a)<<" , "<<(b)<<" )\n"
#define UNIQUE(x) sort(all(x)), x.erase(unique(all(x)), x.end()), x.shrink_to_fit()
template <typename T, typename U> T ceil(T x, U y) {return (x > 0 ? (x + y - 1) / y : x / y);}
template <typename T, typename U> T floor(T x, U y) {return (x > 0 ? x / y : (x - y + 1) / y);}
const int N = 2e5 + 10;
// int tree[N];
int bit1[N];
int bit2[N];
int query(int idx, int *tree) //(Query Time Complexity=O(log(n))
{
int sum = 0;
while (idx > 0)
{
// cout << idx << " ";
sum += tree[idx];
idx -= (idx & -idx);
}
// cout << endl;
return sum;
}
ll RangeSum(int l, int r)
{
ll sum1 = query(r, bit1) * r - query(r, bit2); // Sum of elements in [1, r]
ll sum2 = query(l - 1, bit1) * (l - 1) - query(l - 1, bit2); // Sum of elements in [1, l-1]
return sum1 - sum2; // Sum of elements in [l,r] = Sum of elements in [0,r] - Sum of elements in [0, l-1]
}
void update(int idx, int val, int n, int *tree) //(Update Time Complexity=O(log(n))
{
while (idx <= n)
{
tree[idx] += val;
idx += (idx & -idx);
}
}
void RangeUpdate(int l, int r, int val, int n)
{
update(l, val, n, bit1);
update(r + 1, -val, n, bit1);
update(l, val * (l - 1), n, bit2);
update(r + 1, -val * r, n, bit2);
}
void solve()
{
int n, q;
cin >> n;
vector<int> v(n + 10);
for (ll i = 1; i <= n; i++) // Tree Construction Time Complexity=O(n*log(n))
{
cin >> v[i];
// update(i, v[i], n);
// RangeUpdate(i, i, v[i], n);
}
for(int i = 1; i < n; i++){
if(v[i] > v[i + 1]){
RangeUpdate(i, i, 1, n);
}
}
cin >> q;
while (q--)
{
int type;
cin >> type;
if(type == 1){
int i, x;
cin >> i >> x;
v[i] = x;
int val = RangeSum(i, i);
if(val == 1){
if(i + 1 <= n && v[i] <= v[i + 1]){
RangeUpdate(i, i, -1, n);
}
if(i - 1 > 0 && v[i - 1] <= v[i]){
RangeUpdate(i - 1, i - 1, -1, n);
}
}
else{
if(i + 1 <= n && v[i] > v[i + 1]){
RangeUpdate(i, i, 1, n);
}
if(i - 1 > 0 && v[i - 1] > v[i]){
RangeUpdate(i - 1, i - 1, 1, n);
}
}
}
else{
int l, r;
cin >> l >> r;
int sum = RangeSum(l, r);
if(sum == 0){
cout << "YES" << endl;
}
else if(sum == 1){
if(RangeSum(r, r) == 1){
cout << "YES" << endl;
}
else{
cout << "NO" << endl;
}
}
else{
cout << "NO" << endl;
}
}
}
}
int32_t main()
{
Abid_52;
int t = 1;
// cin >> t;
for (int tc = 1; tc <= t; ++tc)
{
// cout << "Case " << tc << ": ";
solve();
}
}