Accepted
Code
#include <bits/stdc++.h>
using namespace std;
#define ll long long
int main() {
int n;
cin>>n;
if(n%3==0)cout<<n/3;
else{
int x=n%3;
n-=(3*x);
while(n>4){
n-=3;
x++;
}
cout<<x+(n/2);
}
return 0;
}
Information
- Submit By
- Type
- Submission
- Problem
- P1106 too easy or three easy
- Contest
- Brain Booster #6
- Language
- C++17 (G++ 13.2.0)
- Submit At
- 2024-10-03 15:53:50
- Judged At
- 2024-11-11 02:49:41
- Judged By
- Score
- 100
- Total Time
- 1ms
- Peak Memory
- 404.0 KiB