#include <bits/stdc++.h>
using namespace std;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define ll long long
using namespace __gnu_pbds;
typedef tree<int, null_type, less_equal<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
const int mx = 2e5 + 2;
int arr[mx], compressed_arr[mx];
int n;
unordered_map<int, int> compress_map; // To store the mapping from original to compressed
ordered_set st[4 * mx];
// Coordinate Compression Function
void coordinate_compress()
{
vector<int> temp(arr + 1, arr + n + 1);
sort(temp.begin(), temp.end());
temp.erase(unique(temp.begin(), temp.end()), temp.end()); // Remove duplicates
for (int i = 0; i < temp.size(); i++)
{
compress_map[temp[i]] = i + 1; // Assign compressed values starting from 1
}
for (int i = 1; i <= n; i++)
{
compressed_arr[i] = compress_map[arr[i]]; // Compress the original array
}
}
void build(int si, int ss, int se)
{
if (ss == se)
{
st[si].insert(compressed_arr[ss]);
return;
}
int mid = (ss + se) / 2;
build(si * 2, ss, mid);
build(si * 2 + 1, mid + 1, se);
st[si] = st[si * 2];
for (auto x : st[si * 2 + 1])
st[si].insert(x);
}
int query(int si, int ss, int se, int l, int r, int x)
{
if (se < l || ss > r)
return 0;
if (ss >= l && se <= r)
{
int kk = st[si].order_of_key(x);
return kk;
}
int mid = (ss + se) / 2;
return query(si * 2, ss, mid, l, r, x) + query(si * 2 + 1, mid + 1, se, l, r, x);
}
int query1(int si, int ss, int se, int l, int r, int x)
{
if (se < l || ss > r)
return 0;
if (ss >= l && se <= r)
{
int kk = st[si].order_of_key(x + 1);
int sz = st[si].size();
return sz - kk;
}
int mid = (ss + se) / 2;
return query1(si * 2, ss, mid, l, r, x) + query1(si * 2 + 1, mid + 1, se, l, r, x);
}
void solve(int tc)
{
scanf("%d", &n);
for (int i = 1; i <= n; i++)
{
scanf("%d", &arr[i]);
}
coordinate_compress(); // Compress the array before building the segment tree
for (int i = 1; i <= 4 * n; i++)
{
st[i].clear();
}
build(1, 1, n);
int q;
scanf("%d", &q);
int l, x, r;
while (q--)
{
scanf("%d %d %d", &l, &x, &r);
int l1 = query(1, 1, n, l, x - 1, compressed_arr[x]);
int l2 = query1(1, 1, n, x + 1, r, compressed_arr[x]);
long long ans = l1 * l2;
l1 = x - l - l1;
l2 = r - x - l2;
long long tp = l1 * l2;
ans += tp;
printf("%lld\n", ans);
}
}
int main()
{
int t;
scanf("%d", &t);
for (int i = 1; i <= t; i++)
{
solve(i);
}
return 0;
}