/ SeriousOJ /

Record Detail

Accepted


  
# Status Time Cost Memory Cost
#1 Accepted 1ms 328.0 KiB
#2 Accepted 14ms 532.0 KiB
#3 Accepted 28ms 1.27 MiB
#4 Accepted 35ms 1.27 MiB
#5 Accepted 28ms 1.27 MiB
#6 Accepted 51ms 1.141 MiB
#7 Accepted 29ms 1.27 MiB
#8 Accepted 29ms 1.312 MiB
#9 Accepted 51ms 1.211 MiB
#10 Accepted 29ms 1.27 MiB
#11 Accepted 29ms 1.137 MiB
#12 Accepted 32ms 1.312 MiB
#13 Accepted 29ms 1.273 MiB
#14 Accepted 54ms 1.137 MiB
#15 Accepted 57ms 1.27 MiB
#16 Accepted 32ms 1.312 MiB
#17 Accepted 29ms 1.27 MiB
#18 Accepted 35ms 1.27 MiB
#19 Accepted 32ms 1.27 MiB
#20 Accepted 35ms 1.27 MiB

Code

// #pragma GCC optimize("O3,unroll-loops,Ofast")
// #pragma GCC target("avx2")
#include<bits/stdc++.h>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
#define int long long
#define endl '\n'

using namespace std;
using pii = pair<int, int>;
using tup = tuple<int, int, int>;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
// template <class T> using ordered_set = tree<T, null_type,
//                          less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;

const int inf = 1e18;
const int mod = 1000000007;
const double eps = 1e-9;
const int N = 500005;

void preprocess() {}

int a[N];

void solve(int tc) {
    int n;
    cin >> n;

    for(int i=1; i<=n; i++) cin >> a[i];
    int sum = accumulate(a+1, a+n+1, 0ll);
    
    int ans = 1;
    while(ans * (ans + 1) <= 2 * sum) ans++;

    cout << ans << endl;
}   

int32_t main() {
    cin.tie(NULL)->sync_with_stdio(false);
    cout.precision(10);

    preprocess();

    int T = 1;
    cin >> T;

    for (int i = 1; i <= T; i++) {  
        solve(i);
    }

    return 0;
}

Information

Submit By
Type
Submission
Problem
P1114 Maximize the MEX
Contest
Brain Booster #7
Language
C++17 (G++ 13.2.0)
Submit At
2024-11-05 14:59:55
Judged At
2024-11-05 14:59:55
Judged By
Score
100
Total Time
57ms
Peak Memory
1.312 MiB