/ SeriousOJ /

Record Detail

Time Exceeded


  
# Status Time Cost Memory Cost
#1 Accepted 147ms 416.961 MiB
#2 Accepted 149ms 416.949 MiB
#3 Accepted 142ms 416.98 MiB
#4 Accepted 138ms 416.98 MiB
#5 Time Exceeded ≥2022ms ≥437.77 MiB
#6 Time Exceeded ≥2027ms ≥434.621 MiB

Code

// #pragma GCC optimize("O3,unroll-loops,Ofast")
// #pragma GCC target("avx2")
#include<bits/stdc++.h>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;
#define int long long
#define endl '\n'

using namespace std;
using pii = pair<int, int>;
using tup = tuple<int, int, int>;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
// template <class T> using ordered_set = tree<T, null_type,
//                          less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;

const int inf = 1e18;
const int mod = 1000000007;
const double eps = 1e-9;
const int N = 500005;

void preprocess() {}

vector<int> e[N];
int sz[N], mx[N];

void dfs(int u, int p) {
    sz[u] = 1;
    mx[u] = 1;
    for(int v : e[u]) if(v != p) {
        dfs(v, u);
        sz[u] += sz[v];
        mx[u] = max(mx[v] + 1, mx[u]);
    }
}

int dp[N][105];

int DP(int i, int k, int p) {
    if(dp[i][k] != -1) return dp[i][k];
    multiset<int> st;
    for(int j : e[i]) if(j - p) 
        st.insert(mx[j]);

    int ans = 1;
    for(int j : e[i]) if(j - p) {
        st.erase(st.find(mx[j]));
        ans = max(ans, 1 + DP(j, k, i));
        if(st.size()) for(int kk=0; kk<=k; kk++) {
            int now = 1 + DP(j, kk, i);
            now += min(*st.rbegin(), k - kk);

            ans = max(ans, now);
        } 
        st.insert(mx[j]);
    }

    return dp[i][k] = ans;
}

void solve(int tc) {
    int n, k;
    cin >> n >> k;

    for(int i=1; i<n; i++) {
        int u, v;
        cin >> u >> v;
        e[u].push_back(v);
        e[v].push_back(u);
    }

    memset(dp, -1, sizeof dp);
    dfs(1, -1);
    cout << DP(1, k, -1) << endl;
}   

int32_t main() {
    cin.tie(NULL)->sync_with_stdio(false);
    cout.precision(10);

    preprocess();

    int T = 1;
    // cin >> T;

    for (int i = 1; i <= T; i++) {  
        solve(i);
    }

    return 0;
}

Information

Submit By
Type
Submission
Problem
P1111 Thakurs tree game
Contest
Brain Booster #7
Language
C++17 (G++ 13.2.0)
Submit At
2024-11-05 15:33:33
Judged At
2024-11-11 02:30:28
Judged By
Score
15
Total Time
≥2027ms
Peak Memory
≥437.77 MiB