/ SeriousOJ /

Record Detail

Time Exceeded


  
# Status Time Cost Memory Cost
#1 Accepted 1ms 540.0 KiB
#2 Accepted 1ms 540.0 KiB
#3 Accepted 1ms 556.0 KiB
#4 Accepted 1ms 564.0 KiB
#5 Accepted 1ms 540.0 KiB
#6 Accepted 1ms 556.0 KiB
#7 Accepted 1ms 328.0 KiB
#8 Accepted 1ms 588.0 KiB
#9 Accepted 1ms 556.0 KiB
#10 Accepted 1ms 540.0 KiB
#11 Accepted 1ms 540.0 KiB
#12 Accepted 2ms 768.0 KiB
#13 Accepted 1ms 768.0 KiB
#14 Accepted 1ms 540.0 KiB
#15 Accepted 42ms 2.418 MiB
#16 Accepted 37ms 2.629 MiB
#17 Accepted 42ms 2.355 MiB
#18 Accepted 41ms 2.676 MiB
#19 Accepted 42ms 2.527 MiB
#20 Accepted 45ms 2.289 MiB
#21 Accepted 42ms 2.426 MiB
#22 Time Exceeded ≥1100ms ≥1.754 MiB
#23 Time Exceeded ≥1100ms ≥1.777 MiB

Code

/*
 *   Copyright (c) 2025 Emon Thakur
 *   All rights reserved.
 */
#include<bits/stdc++.h>
using namespace std;
bool allone(int a[],int n)
{
    for(int i=1;i<=n;i++)
    {
        if(a[i]!=1) return false;
    }return true;
}
int main()
{
    int n; cin >> n;
    int a[n+1],cnt[n+1],last[n+1];
    for(int i=1;i<=n;i++) cin >> a[i];
    if(allone(a,n))
    {
        for(int i=1;i<=n;i++)
        {
            cout<<n<<' '<<n-i+1<<'\n';
        }
        return 0;
    }
    for(int i=1;i<=n;i++)
    {
        int j = i;
        int cn = 1;
        while(j+a[j] <= n)
        {
            ++cn;
            j += a[j];
        }
        last[i] = j;
        cnt[i] = cn;
    }

    for(int i=1;i<=n;i++) cout<<last[i]<<' '<<cnt[i]<<'\n';
}

Information

Submit By
Type
Submission
Problem
P1171 Frogs and Lily Pads
Language
C++17 (G++ 13.2.0)
Submit At
2025-02-23 16:52:53
Judged At
2025-02-23 16:52:53
Judged By
Score
97
Total Time
≥1100ms
Peak Memory
≥2.676 MiB