#include<bits/stdc++.h>
#define endl '\n'
using namespace std;
using ll = long long;
const int N = 1e5 + 3, mod = 1e9 + 7;
vector<vector<int>> t(4 * N, vector<int> (20, 0));
struct Segment_Tree {
void merge(auto &l, auto &r, auto& Cur) { // <== Change this function
for(int b = 0; b < 20; b++) Cur[b] = l[b] + r[b];
return;
}
void build(int node, int st, int en, vector<int> &arr) { //=> O(N)
if (st == en) {
// t[node] = arr[st];
auto& x = t[node];
bitset<20> b1 = arr[st];
for(int b = 0; b < 20; b++) x[b] = b1[b];
return;
}
int mid = (st + en) >> 1;
build(node << 1, st, mid, arr); // divide left side
build(node << 1 | 1, mid + 1, en, arr); // divide right side
// Merging left and right portion
auto &Cur = t[node];
auto &Left = t[node << 1];
auto &Right = t[node << 1 | 1];
merge(Left, Right, Cur);
return;
}
void update(int node, int st, int en, int idx, int val) { //=> O(log n)
if (st == en) {
auto& x = t[node];
bitset<20> b1 = val;
for(int b = 0; b < 20; b++) x[b] ^= b1[b];
return;
}
int mid = (st + en) >> 1;
if (idx <= mid) update(node << 1, st, mid, idx, val);
else update(node << 1 | 1, mid + 1, en, idx, val);
// Merging left and right portion
auto &Cur = t[node];
auto &Left = t[node << 1];
auto &Right = t[node << 1 | 1];
merge(Left, Right, Cur);
return;
}
auto query(int node, int st, int en, int l, int r) { //=> O(log n)
if (st > r || en < l) { // No overlapping and out of range
return vector<int> (20, 0); // <== careful
}
if (l <= st && en <= r) { // Complete overlapped (l-r in range)
return t[node];
}
// Partial overlapping
int mid = (st + en) >> 1;
auto Left = query(node << 1, st, mid, l, r);
auto Right = query(node << 1 | 1, mid + 1, en, l, r);
auto Cur = vector<int> (20);
merge(Left, Right, Cur);
return Cur;
}
} st1;
ll Pow(ll a, ll b) { // O(log b)
ll ans = 1 % mod;
a %= mod;
if(a < 0) a += mod;
while (b) {
if (b & 1) ans = (ans * a) % mod;
a = (a * a) % mod;
b >>= 1;
}
return ans;
}
int main() {
ios::sync_with_stdio(false); cin.tie(0);
int n, q;
cin >> n >> q;
vector<int> arr(n + 1);
for(int i = 1; i <= n; i++) cin >> arr[i];
st1.build(1, 1, n, arr);
short type;
while(q--) {
cin >> type;
if(type == 1) {
int pos, x;
cin >> pos >> x;
st1.update(1, 1, n, pos, x);
}
else {
int l, r;
cin >> l >> r;
auto x = st1.query(1, 1, n, l, r);
ll ans = 0;
for(int b = 0; b < 20; b++) {
int oddCnt = x[b];
if(oddCnt == 0) continue;
int evenCnt = (r - l + 1) - oddCnt;
ll com = Pow(2, oddCnt - 1) * Pow(2, evenCnt) % mod;
ans += com * Pow(2, b) % mod;
ans %= mod;
if(ans < 0) ans += mod;
}
cout << ans << endl;
}
}
return 0;
}