/ SeriousOJ /

Record Detail

Memory Exceeded


  
# Status Time Cost Memory Cost
#1 Memory Exceeded ≥1074ms ≥64.016 MiB
#2 Memory Exceeded ≥1039ms ≥64.016 MiB

Code

#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
// #define int long long
const int MOD = 1000000007;
#define sz(x) (ll)(x).size()
#define rd ({ll x; cin >> x; x; })
#define dbg(x) cerr << "[" #x "]  " << (x) << "\n"
// #define errv(x) {cerr << "["#x"]  ["; for (const auto& ___ : (x)) cerr << ___ << ", "; cerr << "]\n";}
// #define cerr if(0)cerr
#define xx first
#define yy second
mt19937 rnd(std::chrono::high_resolution_clock::now().time_since_epoch().count());
/*_________________________________________________________________________________________________________________________*/
vector<ll> divi[1000001];
ll precalc[1000001];
void Solve()
{
    ll n;
    cin >> n;
    cout << precalc[n] << "\n";
}

int32_t main()
{
    for (int i = 1; i <= 1000000; i++)
        for (int j = 2 * i; j <= 1000000; j += i)
            divi[j].push_back(i);
    for (ll i = 2; i <= 1000000; i++) {
        for (auto& it : divi[i]) {
            ll calc = i - it;
            if (__gcd(i, calc) == it) {
                precalc[i]++;
            }
        }
        precalc[i] += precalc[i - 1];
    }
    ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    int t = 1;
    cin >> t;
    for (int i = 1; i <= t; i++) {
        // cout << "Case #" << i << ": "; // cout << "Case " << i << ": ";
        Solve();
    }
    return 0;
}
// Coded by Tahsin Arafat (@TahsinArafat)

Information

Submit By
Type
Submission
Problem
P1206 D1. GCD equal Absolute Value (Easy Version)
Contest
Educational Round 1
Language
C++17 (G++ 13.2.0)
Submit At
2025-07-14 16:45:24
Judged At
2025-07-14 16:45:24
Judged By
Score
0
Total Time
≥1074ms
Peak Memory
≥64.016 MiB