1 solutions

  • 0
    @ 2024-11-05 23:21:18
    #include <bits/stdc++.h>
    using namespace std;
    #define SC               scanf
    #define PF               printf
    #define ull              unsigned long long
    #define ld               long double
    #define F                first
    #define S                second
    #define pb               push_back
    #define sort_a(a)        sort(a.begin(),a.end());
    #define sort_d(a)        sort(a.rbegin(),a.rend());
    #define READ(f)          freopen(f, "r", stdin)
    #define WRITE(f)         freopen(f, "w", stdout)
    #define rev(s)           reverse(s.begin(),s.end())
    #define P(ok)            cout << (ok ? "YES\n": "NO\n")
    #define __Heart__              ios_base :: sync_with_stdio(false); cin.tie(NULL);
    #define ll long long
    typedef pair< ll, ll>                   PII;
    const int mx = 3e5 + 5;
    int K , Ans[mx], arr[mx],freq[mx] , F[mx] ;
    struct Query
    {
        int index, l, r ;
        bool operator < (const Query &other)const
        {
            int block_own = l/ K ;
            int block_other = other.l / K ;
            return(block_other == block_own) ? r < other.r : block_own < block_other ;
        }
    
    } query[mx];
    void add(int index)
    {
        freq[arr[index]]++ ;
    }
    void remove (int index)
    {
       freq[arr[index]]-- ;
    }
    void solve()
    {
        int n , q ; cin >> n >> q ;
        for(int i = 0 ; i < n ; i++) cin >> arr[i] ;
        K = sqrt(n) ;
        for(int i = 0 ; i < q ; i++) cin >> query[i].l >> query[i].r , query[i].index = i  , query[i].l-- , query[i].r--;
        sort(query , query + q) ;
        int l = 0, r = -1 ;
        default_random_engine rd;
        for(int i = 0 ; i < q ; i++)
        {
            while(r < query[i].r) add(++r ) ;
            while(l < query[i].l) remove(l++) ;
            while(r > query[i].r) remove(r-- );
            while(l > query[i].l) add(--l) ;
            int val = INT_MAX;
            uniform_int_distribution <int> distribution(query[i].l , query[i].r);
            int low = (query[i].r - query[i].l + 1) /  3 ;
            for(int j = 0; j < 100; j++){
                int x = distribution(rd);
                if(freq[arr[x]] > low) val = min(val , arr[x]) ;
            }
            if(val == INT_MAX) val = -1;
            Ans[query[i].index] = val;
        }
        for(int i = 0 ; i < q ; i++) cout<< Ans[i] << "\n" ;
    }
    int main()
    {
         __Heart__
        // READ("input7.txt") ;
       // WRITE("output7.txt") ;
         int t ; t = 1 ; while(t--) solve() ;
    }
    
    
  • 1

Information

ID
1103
Difficulty
8
Category
Data_Structure | Math | Probability , Divide_and_Conquer Click to Show
Tags
# Submissions
171
Accepted
16
Accepted Ratio
9%
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